StockFetcher Forums · Filter Exchange · Trend acceleration/deceleration filter<< >>Post Follow-up
9 posts
msg #117624
Ignore abelduarte
1/7/2014 2:51:03 PM

Fetcher[draw MACD Histogram(12,26,9)

draw Linear Regression(45)
draw Linear Regression(200)
and close above ma(200)
and Linear Regression Slope(200) above 0

draw Linear Regression Slope(45)
draw Linear Regression Slope(200)

set {reg45avg, cma(Linear Regression Slope(45), 45)}
set {reg200avg, cma(Linear Regression Slope(200), 200)}

set {slopeofslope45, 45 day slope of Linear Regression Slope(45)}
set {zero45, 0}

set {slopeofslope200, 200 day slope of Linear Regression Slope(200)}
set {zero200, 0}

draw slopeofslope45
draw slopeofslope200
draw zero45 on plot slopeofslope45
draw zero200 on plot slopeofslope200

Having played around with Linear regression a lot as of lately I decided to take it 1 step further and apply physics concepts to it. A stocks linear regression line slope is not the same today as it was yesterdays, the change in this slope can whether up or down can tell us whether a trend is accelerating or slowing down.

StockFetcher Forums · Filter Exchange · Trend acceleration/deceleration filter<< >>Post Follow-up

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